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a fault in our stars - Sourci

📅 May 1, 2026 👤 scraface

May 01, 2026

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Solution: Group and complete the square:
$ 4(x^2 + 6x) - 9(y^2 - 2y) = -9 $.
Complete squares:
$ 4[(x+3)^2 - 9] - 9[(y-1)^2 - 1] = -9 $.
$ 4(x+3)^2 - 36 - 9(y-1)^2 + 9 = -9 $.
$ 4(x+3)^2 - 9(y-1)^2 = 18 $.
Divide by 18:
$ rac{(x+3)^2}{4.5} - rac{(y-1)^2}{2} = 1 $.
Center at $ (-3, 1) $. Final answer: oxed{(-3,\ 1)}
Question: Let $ z $ and $ w $ be complex numbers such that $ z + w = 2...

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