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📰 Then $ x = 1 $, $ z = 4 $, so $ \mathbf{v} = \langle 1, 0, 4 \rangle $
📰 \langle 1, 0, 4 \rangle \times \langle 2, -1, 3 \rangle = \langle (0)(3) - (4)(-1), -[(1)(3) - (4)(2)], (1)(-1) - (0)(2) \rangle = \langle 0 + 4, -(3 - 8), -1 - 0 \rangle = \langle 4, 5, -1 \rangle
📰 Thus, the general solution is a line, but a particular solution is:
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