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Home » Aquí, $ n = 6 $, $ k = 4 $, $ p = \frac12 $. Sustituyendo: - Sourci

Aquí, $ n = 6 $, $ k = 4 $, $ p = \frac12 $. Sustituyendo: - Sourci

📅 May 2, 2026 👤 scraface

May 02, 2026

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We are looking for a two-digit integer $ x $ such that $ x + 3 $ is di...
This means $ x + 3 $ is a common multiple of $ 7, 8, $ and $ 9 $.
First, compute the least common multiple (LCM) of $ 7, 8, $ and $ 9 $:
\text{lcm}(7, 8, 9) = \text{lcm}(7, \text{lcm}(8, 9)) = \text{lcm}(7,...
So $ x + 3 = 504k $ for some integer $ k $.
We want $ x $ to be a two-digit number, so:
x = 504k - 3
Try $ k = 1 $:
x = 504(1) - 3 = 501 \quad \text{(too large)}
Try $ k = 0 $:

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