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Home » Calculate \( 1.12^8 \approx 2.4760 \) - Sourci

Calculate \( 1.12^8 \approx 2.4760 \) - Sourci

📅 May 1, 2026 👤 scraface

May 01, 2026

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📌 Represent placing 3 ones with at least one zero between each. First place 3 ones with a zero between each: 1 0 1 0 1 → uses 5 positions, leaving $ 8 - 5 = 3 $ zeros to distribute freely in the 4 gaps: before first 1, between first and second, between second and third, and after third.

📌 Let the number of extra zeros in these 4 gaps be $ x_1, x_2, x_3, x_4 \geq 0 $, with sum $ x_1 + x_2 + x_3 + x_4 = 3 $

📌 Number of non-negative integer solutions: $ \binom{3 + 4 - 1}{3} = \binom{6}{3} = 20 $

📌 So there are 20 valid configurations (binary strings) with exactly 3 non-adjacent 1s.

📌 For each such configuration, the probability is:

📌 \left(\frac{1}{3}\right)^3 \left(\frac{2}{3}\right)^5 = \frac{1^3 \cdot 2^5}{3^8} = \frac{32}{6561}

📌 Since each configuration has the same probability and they are mutually exclusive:

📌 Total probability:

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