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Subtract \( \frac{28.8}{\pi} \approx 9.17 \), so \( h^{5/2} \approx 489.65 \) → \( h \approx (489.65)^{2/5} \approx (489.65)^{0.4} \approx 14.3 \) — but check: 12 to lower? Wait: negative sign means decreasing.
Actually: \( h^{5/2} = 498.816 - 9.17 = 489.65 \) → \( h = (489.65)^{2/5} \).
\( 489.65^{0.4} \): \( \ln(489.65) \approx 6.19 \), \( 0.4 \times 6.19 = 2.476 \), \( e^{2.476} \approx 11.94 \).

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