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📰 But wait—this is quadratic, but the problem states $ p(x) $ is cubic. Contradiction? Not necessarily—$ a = 0 $ is allowed if the cubic coefficient is zero, but the problem says cubic, implying degree exactly 3. So we must assume it's cubic, but our solution gives $ a = 0 $. That means the data fits a quadratic, but we are told it's cubic. So either the model is misclassified, or we must accept the interpolating polynomial, regardless of degree. Since the interpolation yields a unique cubic (degree at most 3), and we found $ a = 0 $, the polynomial is actually quadratic. But the problem says cubic, so we must reconsider. 📰 Wait—perhaps the problem allows degree ≤ 3. Many contest problems phrase cubic loosely. Given the values fit a quadratic, and no higher-degree terms are forced, the minimal-degree interpolating polynomial is quadratic. Since the problem asks to find $ p(0) $, and the unique cubic polynomial (in degree ≤ 3) satisfying the values must have $ a = 0 $, we proceed with $ p(x) = 2x^2 + x $, so $ p(0) = 0 $. However, to ensure degree 3, suppose we include a zero cubic term. Then $ p(x) = 0x^3 + 2x^2 + x + 0 $, and $ p(0) = 0 $. 📰 But let's verify all values: 📰 Red Dead Redemption 2 Steam Deck 6775595 📰 You Wont Believe Whats Hidden On The Map Prsecret Treasures Revealed 4179784 📰 Best L Ascorbic Acid Serums 6683467 📰 Police Reveal Verizon Presale Kali Uchis And The World Reacts 📰 Low Red Distribution Width 734999 📰 Love Poetry Love 📰 Circle K App 📰 Shock Moment Pokemon Mystery Dungeon Red Rescue Team And It Sparks Outrage 📰 Bank Of America Open Account Non Resident 8262735 📰 Gaara And His Hidden Power The Secret That Changed Sands Destiny Forever 231522 📰 Bank Of America Login Mobile 9268360 📰 From Beginner To Hardcore Leveling Warrior Watch The Journey That Changed Her Life Forever 3964877 📰 Fidelity 401K Investments 4152065 📰 Livesql Oracle 📰 Wall Of Shame Hipaa