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📅 April 30, 2026 👤 scraface

Apr 30, 2026

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📌 The sum of the squares of three consecutive integers is 425. What is the smallest of these integers?

📌 Sum of squares:

📌 \[ (n-1)^2 + n^2 + (n+1)^2 = 425 \]

📌 \[ (n^2 - 2n + 1) + n^2 + (n^2 + 2n + 1) = 425 \]

📌 \[ 3n^2 + 2 = 425 \]

📌 \[ 3n^2 = 423 \]

📌 \[ n^2 = 141 \]

📌 \[ n = \sqrt{141} \approx 11.87 \]

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