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Startwert: 100 Einheiten - Sourci

📅 May 1, 2026 👤 scraface

May 01, 2026

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📌 Set $ h'(x) = 0 $ to find where the slope is horizontal:

📌 3x^2 - 6x + 2 = 0

📌 Solve using the quadratic formula:

📌 x = \frac{6 \pm \sqrt{(-6)^2 - 4 \cdot 3 \cdot 2}}{2 \cdot 3} = \frac{6 \pm \sqrt{36 - 24}}{6} = \frac{6 \pm \sqrt{12}}{6} = \frac{6 \pm 2\sqrt{3}}{6} = 1 \pm \frac{\sqrt{3}}{3}

📌 The sum of the roots is:

📌 \left(1 + \frac{\sqrt{3}}{3}\right) + \left(1 - \frac{\sqrt{3}}{3}\right) = 2

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