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📰 But $ d(t) = t^3 $ is strictly convex and has no minimum (it decreases on $ (-\infty, 0) $, increases on $ (0, \infty) $), so it does not achieve a minimum. However, the problem states that the **minimum depth is achieved exactly once**, which implies $ d(t) $ has a unique global minimum. But $ t^3 $ has no such minimum. Contradiction? 📰 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions. 📰 But $ d(t) = t^3 $ has no minimum. Unless minimum depth refers to **local minimum**? But still, $ t^3 $ has no local minimum. 📰 Transform Fabric Into Stunning Art Try This Must Have Granny Square Crochet Pattern 4960202 📰 Verizon Pending Order 📰 Anima Engine Download 6547556 📰 Breaking Aon Stock Price Soars Todaydid You Know How Fast It 8733638 📰 Image Merger 📰 Big Update Mahjong Connect And The Truth Shocks 📰 New Notre Dame Logo 1162130 📰 Recollection Suffix 1991564 📰 Action Replay Codes For Pokemon Black 📰 Grow A Garden Mutation List 📰 Where Earth Touches Heaven Natures Most Breathtaking Gems 3832028 📰 M4 Mac Mini 📰 Anime Royale 📰 Flights To Kauai Hawaii 3516437 📰 Why All The Buzz About Capers Heres What Makes Their Taste Unforgettable 3459765