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the avery on southwestern dallas tx 75214 - Sourci

📅 May 1, 2026 👤 scraface

May 01, 2026

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Use the Pythagorean identity: \( \sin^2(x) + \cos^2(x) = 1 \).
So, \( \left(\frac{3}{5}\right)^2 + \cos^2(x) = 1 \) gives \( \frac{9}...
Solving for \( \cos^2(x) \) gives \( \cos^2(x) = 1 - \frac{9}{25} = \f...
Since \( x \) is in the first quadrant, \( \cos(x) = \frac{4}{5} \).
#### \(\frac{4}{5}\)
The function \( f(x) = x^3 - 3x^2 + 4 \) has a local minimum at \( x =...
First, find the derivative: \( f'(x) = 3x^2 - 6x \).
Set \( f'(x) = 0 \) to find critical points: \( 3x(x - 2) = 0 \).
So, \( x = 0 \) or \( x = 2 \).
Use the second derivative test: \( f''(x) = 6x - 6 \).

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