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Home » The Hidden Truth Behind Hinata Naked: Five Eyes-Grabbing Surprises! - Sourci

The Hidden Truth Behind Hinata Naked: Five Eyes-Grabbing Surprises! - Sourci

📅 May 2, 2026 👤 scraface

May 02, 2026

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\lim_{n \to \infty} a_n = \lim_{n \to \infty} \sum_{k=1}^{n} \left( \f...
This is a Riemann sum. Split the sum:
a_n = \sum_{k=1}^{n} \frac{k}{n} - \frac{1}{3} \sum_{k=1}^{n} \left( \...
= \frac{1}{n} \sum_{k=1}^{n} k - \frac{1}{3n^3} \sum_{k=1}^{n} k^3
Use formulas:
$ \sum_{k=1}^{n} k = \frac{n(n+1)}{2} $
$ \sum_{k=1}^{n} k^3 = \left( \frac{n(n+1)}{2} \right)^2 $
a_n = \frac{1}{n} \cdot \frac{n(n+1)}{2} - \frac{1}{3n^3} \cdot \left(...
= \frac{n+1}{2} - \frac{1}{3n^3} \cdot \frac{n^2(n+1)^2}{4}
Simplify the second term:

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