A student mixes 200 mL of 30% acid solution with 300 mL of 60% acid solution. What is the concentration of the resulting mixture?

Thu, 30 Apr 2026 14:13:35 +0000

**Why Is This Acid Mixing Exercise Gaining Curiosity in the US?**
A student mixes 200 mL of a 30% acid solution with 300 mL of a 60% acid solution. On the surface, this appears to be an everyday science problem—yet it’s sparking quiet fascination across US education and chemistry circles. As students explore concentration dynamics, this scenario reflects broader trends in STEM learning: hands-on problem solving supported by accessible tools and real-world relevance. With growing emphasis on chemistry fluency for future careers, curious learners are drawn to practical mixtures—safe, structured exercises that build confidence and critical thinking. Beyond classroom learning, the scenario taps into a larger cultural interest in chemical reactions and mixtures. From online study communities to educational platforms, students and educators alike are discussing how dilution and strength interact. This moment reflects a seasonal uptick in chemistry-focused curiosity, driven by academic pressure, hands-on learning projects, and the increasing demand for STEM literacy in a technology-driven economy. **How Does Mixing 200 mL of 30% Acid with 300 mL of 60% Acid Actually Work?**
When 200 mL of a 30% acid solution is combined with 300 mL of a 60% acid solution, the resulting mixture is not a simple average but a weighted average based on volume and concentration. The total volume becomes 500 mL, calculated by adding 200 mL and 300 mL. The total acid content comes from two parts: 30% of 200 mL plus 60% of 300 mL. This combination determines the final concentration through volume-weighted proportion—not arithmetic mean. Understanding this mixing principle reveals the precision required in chemistry and industry applications alike. The process works through basic mass and proportion logic. The 30% solution contributes 60 mL of pure acid (200 × 0.30), while the 60% solution contributes 180 mL (300 × 0.60). Together, 240 mL of acid are distributed across 500 mL of total solution. Converting that to percentage yields 240 ÷ 500 = 0.48 or 48%. This weighted average ensures accuracy regardless of initial volumes.