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📅 April 30, 2026 👤 scraface

Apr 30, 2026

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First, calculate the discriminant:
\[ b^2 - 4ac = (-5)^2 - 4 imes 2 imes (-3) = 25 + 24 = 49 \]
Then find the roots:
\[ x = rac{-(-5) \pm \sqrt{49}}{2 imes 2} = rac{5 \pm 7}{4} \]
The solutions are:
\[ x = rac{5 + 7}{4} = 3 \quad ext{and} \quad x = rac{5 - 7}{4} = -...
Thus, the values of \( x \) are 3 and \(-rac{1}{2}\).
Evaluate the expression \( rac{3}{4} \cdot rac{8}{9} + rac{1}{3} -...
First, simplify each term:
\[ rac{3}{4} \cdot rac{8}{9} = rac{24}{36} = rac{2}{3} \]

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